Saturday, November 17, 2012
MECHANICAL ENGINEERING: Design of Machine Elements - Rod with a circular cross-section
FS = S/Sa
Sa = F/A
A = pi/4 * d^2
A = 0.785 * d^2
A = pi * r^2
A = 3.14 * r^2
where:
FS = factor of safety
S = strength of the material
Sa = allowable stress
F = Force applied
A = cross-sectional area of material
r = radius of circular rod
d = diameter of circular rod
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1. Problem: Circular Rod
Determine the safe size of a circular rod to be loaded with an axial force of 3000 lbs considering a factor of safety of 4 and the material strength of the rod 30,000 psi.
find:
d = diameter of circular rod
given:
F = axial force = 3000 lbs
S = material strength = 30,000 psi
FS = factor of safety = 4
solution:
Sa = F/A
Sa = 3000/0.785 d^2
Sa = 3821.66 d^2 ---> equation1
FS = S/Sa
4 = 30,000/Sa
Sa = 30,000/4
Sa = 7500 ---> equation2
equation2 in equation1
Sa = 3821.66 d^2
7500 = 3821.66 d^2
d^2 = 1.96
d = 1.4 in ---> use 1.5 in
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I was wondering if anyone could help me find some cad software that would be ideal for structural engineering type of things where u plug in numbers and it will tell u the measurements of the metal and etc.,,. i have googled it a zillion times and there are so many types of cad software i really don't know what to pic...........thanks its for an aerospace contract i believe. also by aerospace contract i just mean that i have to build parts, and etc.
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