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REFRIGERATION HVAC MECHANIC RED SEAL LICENSE EXAM REVIEWER - capacitance of series capacitors
PROBLEM:
Two capacitors are wired in series. The capacitance of the first capacitor is 50 micro Farads (uF). If the second capacitor has 150 uF, solve for the total capacitance of the circuit.
Given
wiring = series
capacitance1 = 50 uF
capacitance2 = 150 uF
Unknown
Total capacitance of circuit
SOLUTION:
Series Capacitors:
Total Capacitance Ct = 1/ [ (1/C1) + (1/C2) ]
Ct = 1/ [ (1/50) + (1/150) ]
Ct = 1/(0.02 + 0.0067)
Ct = 1/0.0267
Ct = 37.5 uF
Alternate formula:
Ct = C1 x C2 / ( C1 + C2 )
Ct = 50 x 150 / (50 + 150)
Ct = 7500/200
Ct = 37.5 uF
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